Odpowiedź w załączniku.....
log3 ∛0,(1)
0,(1)=1/9
log3∛[(1/9)=log3 (3^-2)^1/3=log3 3^-2/3=-2/3log3 3=-2/3·1=-2/3
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Odpowiedź w załączniku.....
log3 ∛0,(1)
0,(1)=1/9
log3∛[(1/9)=log3 (3^-2)^1/3=log3 3^-2/3=-2/3log3 3=-2/3·1=-2/3