a) log100+log1=log(100·1)=log100=log10²=2log10=2·1=2
b) log8+log125=log(8·125)=log(2³·5³)=log(2·5)³=log(2·50=3log`10=3·1=3
c) log7+log3=log(7·3)=log21
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a) log100+log1=log(100·1)=log100=log10²=2log10=2·1=2
b) log8+log125=log(8·125)=log(2³·5³)=log(2·5)³=log(2·50=3log`10=3·1=3
c) log7+log3=log(7·3)=log21