Oblicz jaka objętość (w warunkach normalnych)zajmuja:
a) 2mole NO
b)92g NO2
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Oblicz jaka objętość (w warunkach normalnych)zajmuja:
a) 2mole NO
b)92g NO2
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a) 1mol NO -22,4dm^3
---2mole NO - x
x=2mole*22,4dm^3=44,8dm^3
b)masa NO2 = 14g * + 2*16g =46g
1 mol NO2 = 46g
46g NO2 - 22,4dm^3
92g NO2 - x
x= (92g * 22,4dm^3)/46g = 44,8dm^3