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V=3*4*3
V=36
azot≈78%
0,78*36≈28,08 m³
zawartośc azotu w powietrzu ok. 79%
100%-36
79%-x
x=2844/100=28.44 dm3
zawartość % azotu= 78%
78% z 36
78% * 36 =28,08