oblicz jaką masę ma 0,5m3 azotu odmierzonego w warunkach normalnych?
1mol ------------ 22,4dm³
x mol ------------ 0,5m³ = 500dm³
22,4x = 500 |:22,4
x ≈ 22,32 [mol]
M N2 = 2*14g/mol = 28g/mol
m N2 = 28g/mol*22,32mol = 624,96g
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1mol ------------ 22,4dm³
x mol ------------ 0,5m³ = 500dm³
22,4x = 500 |:22,4
x ≈ 22,32 [mol]
M N2 = 2*14g/mol = 28g/mol
m N2 = 28g/mol*22,32mol = 624,96g