oblicz ile moli stanowi a)5,6 dm3 azotu N2
b)44,8 dm3 chloru Cl2
a)
1 mol N2 ---- 22,4dm3
X ---- 5,6dm3
X=0,25 mola
b)
1 mol Cl2 ---- 22,4dm3
X ---- 44,8dm3
X=2 mole
a) 1 mol --- 22,4dm3x moli --- 5,6 dm3x= 5,6dm3 * 1 mol / 22,4 dm3 = 0,25 mola = 1/4 mola b) 1 mol --- 22,4 dm3x moli --- 44,8dm3 x = 44,8dm3 *1 mol / 22,4dm3 = 2 molePozdrawiam, kate66 ;)
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a)
1 mol N2 ---- 22,4dm3
X ---- 5,6dm3
X=0,25 mola
b)
1 mol Cl2 ---- 22,4dm3
X ---- 44,8dm3
X=2 mole
a)
1 mol --- 22,4dm3
x moli --- 5,6 dm3
x= 5,6dm3 * 1 mol / 22,4 dm3 = 0,25 mola = 1/4 mola
b)
1 mol --- 22,4 dm3
x moli --- 44,8dm3
x = 44,8dm3 *1 mol / 22,4dm3 = 2 mole
Pozdrawiam, kate66 ;)