Oblicz ile moli kwasu octowego potrzeba do przygotowania 250g 10%-owego roztworu.
Z def. stęż. procent.
10g kwasu----100g roztworu
xg kwasu------250g roztworu
x = 25g kwasu
M CH3COOH=60g/mol
60g CH3COOH----1mol
25g CH3COOH------xmoli
x = 0,42mole CH3COOH
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Z def. stęż. procent.
10g kwasu----100g roztworu
xg kwasu------250g roztworu
x = 25g kwasu
M CH3COOH=60g/mol
60g CH3COOH----1mol
25g CH3COOH------xmoli
x = 0,42mole CH3COOH