Oblicz ile kg kwasu octowego powstanie w wyniku fermentacji octowej wiedząc że jednocześnie powstaje 125 kg wody.
46u 18u
C₂H₅OH + O₂ --> CH₃COOH + H₂O
x 125kg
x = 319,22kg
46u 60u
319,22kg y
y = 416⅔kg
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)
C2H5OH+O2------>CH3COOH+H2O
x 125g
mH2O=18u
mCH3COOH=60u
125g-------------18u
x------------------60u
x=416,7g CH3COOH
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46u 18u
C₂H₅OH + O₂ --> CH₃COOH + H₂O
x 125kg
x = 319,22kg
46u 60u
C₂H₅OH + O₂ --> CH₃COOH + H₂O
319,22kg y
y = 416⅔kg
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)
C2H5OH+O2------>CH3COOH+H2O
x 125g
mH2O=18u
mCH3COOH=60u
125g-------------18u
x------------------60u
x=416,7g CH3COOH