oblicz ile jonów wapnia znajdujee się w 5g fosforaanu V wapnia?
Ca3(PO4)2--------->3Ca^2+ + 2PO4^3-
M=310g
310g Ca3(PO4)2------------------3moleCa^2+
5g--------------------------------------xmola=0,048mola
0,048*6,02*10^23=2,88*10^22
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Ca3(PO4)2--------->3Ca^2+ + 2PO4^3-
M=310g
310g Ca3(PO4)2------------------3moleCa^2+
5g--------------------------------------xmola=0,048mola
0,048*6,02*10^23=2,88*10^22