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128 g Na2O ----- x g NaOH
62 g Na2o ------- 80g NaOH
62x=10240g /:62
x=165,16g= 165,2g
Otrzymamy 165.2g NaOH
mNaOH=23u+1u+16u=40u
Na2O + H2O----->2NaOH
62g Na2O-------2*40g NaOH
128g Na2O-------xg NaOH
x=128*80/62
x=165g NaOH