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MgO+2HNO3--->Mg(NO3)2 + H2O
mMgO =40
mMg(NO3)2=132
udziały w reakcji:
Mg(NO3)2=29,6
MgO=?
X g MgO--- 29.6g Mg(NO3)2
40 g MGO ---132Mg(NO3)2
X=8,97g