Oblicz ile gramów tlenku magnezu powstanie w reakcji 36 g magnezu z tlenem.
2Mg+O2--->2MgO
36g---------xg
48g--------80g
x=60g
O₂ + 2Mg -> 2 MgO
48,6g ----------80,6g
36g-------------x
x=(80,6g *36g)/48,6g = 59,7 g
powstanie 59,7g MgO
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2Mg+O2--->2MgO
36g---------xg
48g--------80g
x=60g
O₂ + 2Mg -> 2 MgO
48,6g ----------80,6g
36g-------------x
x=(80,6g *36g)/48,6g = 59,7 g
powstanie 59,7g MgO