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mNa=23u
23u*2=46u
mNaCl=23u+35,5u=58,5u
2*58,5u=117u
2*23g Na - 2*58,5g NaCl
9,2g Na - xg NaCl
46g Na - 117g NaCl
9,2g Na - xg NaCl
x=(9,2g Na*117g NaCl)/46g Na=23,4g NaCl
Odp. Powstanie 23,4g NaCl.
MNa=23g/mol MNaCl=58.5g/mol
układam proporcję:
46g Na- 117g NaCl
9.2g- xg NaCl
x=23.4g NaCl powstanie