Oblicz ile gram tlenu potrzeba do całkowitego spalenia 200 g metanu
mCH4=16u
mO2=32u
CH4 + 2 O2---->CO2 + 2H2O
16g metanu------2*32g tlenu
200g metanu-------xg tlenu
x = 800g tlenu
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mCH4=16u
mO2=32u
CH4 + 2 O2---->CO2 + 2H2O
16g metanu------2*32g tlenu
200g metanu-------xg tlenu
x = 800g tlenu