February 2019 0 13 Report
Oblicz entalpię reakcji
Fe2O3(s) + 2Al(s) = 2Fe(s) + Al2O3
mając dane
4Fe(s) + 3O2(g) = 2Fe2O3(s) delta h = -1644 kJ
4Al(s) + 3O2(g) = 2Al2O3(s) delta h = -3340kj

Mógł by mi ktoś to wytłumaczyć?

More Questions From This User See All

Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.