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(√3x)^2+(x+1)^2=(2-2x)^2
3x^2+x^2+2x+1=4-8x+4x^2
4x^2+2x+1-4+8x-4x^2=0
10x-3=0
10x=3/:10
x=0,3
czyli 0,3√3; 1,3; 2-2*0,3=1,4