Oblicz długość łuków:
A.Alfa=135 stopni,r=20
B.Alfa=120 stopni,r=12
C.Alfa=200 stopni,r=15
PROSZĘ O POMOC.
a)
l = alfa/360*2πr=135/360*2 π20=0,375*40 π = 15 π cm
P=alfa/360*πr^2=135/360* π20^2= 0,375*400 π= 150 π cm^2
b)
l = alfa/360*2πr=120/360*2 π12= 1/3*24 π= 8 π cm
P=alfa/360*πr^2=120/360 π12^2=1/3*144 π= 48 π cm^2
c)
l = alfa/360*2πr=200/360*2 π15= 200/360*30 π= 600/36 π= 150/9 π cm
P=alfa/360*πr^2=200/360* π15^2= 200/360*225 π= 45000/360 π = 125 π cm^2
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a)
l = alfa/360*2πr=135/360*2 π20=0,375*40 π = 15 π cm
P=alfa/360*πr^2=135/360* π20^2= 0,375*400 π= 150 π cm^2
b)
l = alfa/360*2πr=120/360*2 π12= 1/3*24 π= 8 π cm
P=alfa/360*πr^2=120/360 π12^2=1/3*144 π= 48 π cm^2
c)
l = alfa/360*2πr=200/360*2 π15= 200/360*30 π= 600/36 π= 150/9 π cm
P=alfa/360*πr^2=200/360* π15^2= 200/360*225 π= 45000/360 π = 125 π cm^2