Oblicz dlugosci przekątnych czworokąta ABCD , jeśli A=(-1,0), B=(3,2), C=(2,4), D=(-2,2)
I AC I=√[(2+1)²+(0-4)²]=√[9+16]=5
I BDI=√[(-2-3)²+(2-2)²]=√25=5
AC=
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I AC I=√[(2+1)²+(0-4)²]=√[9+16]=5
I BDI=√[(-2-3)²+(2-2)²]=√25=5
AC=