Question

Oblicz dlugosc odcinka AB jezeli A=(-8,6) B=(0,0) 2) A=(-5,4) B=(1,-2) DZIEKI

Answer 1

8² + 6² = x²

64 + 36 = x²

100 = x²

10 = x

|AB| = 10

 

6² + 6² = y²

36 + 36 = y²

72 = y²

2√6 = y

Answer 2

AB=√[(0+8)²+(0-6)²]=√[64+36]=√100=10

 

AB=√[(1+5)²+(-2-4)²]=√[36+36]=√72=6√2