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S-0,1m²
Ft-sila tloka=100n
h-1m
Szukane:
p=?
Fn-sila nacisku wody
Fc= Ft+Fn
Rozwiązanie:
V=S*h=0,1*1=0,1m³
0,1m³=100dm³=100l
Fn=mg
Fn=100*10=1000N
Fc=Fn+Ft
Fc=1100N
p=Fc/S
p=1100/0,1=11000Pa
Cisnienie calkowite to 11000Pa