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tg10
tg80=tg(90-10)=ctg10 otrzymujemy zatem tg10ctg10=1
tg20
tg70=tg(90-20)=ctg20 ; tg20ctg20=1
tg30
tg60=tg(90-30)=ctg30 ;tg30ctg30=1
tg40
tg50=tg(90-40)=ctg40 ; tg40ctg40=1
A zatem wartosc wyrazenia wynosi
1*1*1*1=1
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Wykorzystano zwiazek
tgαctgα=1 gdy sinα≠0 ∧ cosα≠0