Question

Oblicz
a=log₀,₅ 2⁻⁵=
b=log₃3¹⁵-log₃27=

Answer 1

(0,5)^a=2^(-5)
(1/2)^a=2^(-5)
(2^-1)^a=2^(-5)
-a=-5
a=5

b=log na dole 3 z (3^15:27)
b=log o podstawie 3 z (3^15:3^3)
b=log o podstawie 3 z 3^12
b=12