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S=32/82*100%=16/41*100%=39,02%
S=39,02%
O=3*16/82*100%=48/82*100%=24/41*100%=58,53%
O=58,53%
b)H:S:O H₂SO₃
H=1u*2
S=32u
O=16*3=48u
2:32:48 /:2
stosunek masowy: 1:16:24
c)tlenek siarki-SO₂
S=32u
O=16u*2=32u
32:32 /:32
stosunek masowy: 1:1
S-32u
O-16u
m=2*1+32+3*16
m=82uO
%O=?
82u-100%
48u-O%
O=(48*100%)/82
O=58,54%
%S=?
82u-100%
32u-S%
S=(32*100%)/82
S=39,02%
b)
st.mas=2:32:48:=1:16:24
c)
S=32u
O=16u*2
st.mas=32:32=1:1