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a)
Ca:C:O
40:12:48 /przez 4
10:3:12
b)
masa cząsteczkowa: 40+12+48=100g
Ca: 40/100 x 100%=40%
C: 12/100 x 100%=12%
O: 48/100 x 100%=48%
CaCO3
40:12:48
20:6:24
10:3:12
b) procent masowy pierwiastków w weglanie wapnia.
mCaCO3 = 40 + 12+16*3 = 52 +48= 100
%Ca = 40 100
---- X ------ = 40%
100 1
%C= 12 100
------ X ------- = 12 %
100 1
%O=100%- (40%+12%) = 100%- 52% = 48%