Question

Oblicz :
a) log₂(3+log10)
b) log₂(3-log100)
c)log₂(log√10)
d)log₉(log∛10)
e)log₂2¹⁰⁰-log 100¹⁰)

Answer 1

A) log₂(3+log10)= log[2] (4) = 2
b) log₂(3-log100)= log[2] (1) = 0
c)log₂(log√10)= log[2] (1/2) = -1
d)log₉(log∛10)= log[9] (1/3) = -1/2
e)log₂2¹⁰⁰-log 100¹⁰= 100 - 20 = 80