Oblicz :
a) 3(a+2b-3c) - 2 (a-2c)+5(c-b)-(a+b)=
b) am(a+1)-2( do kwadratu ) =
a)
3(a+2b-3c) - 2 (a-2c)+5(c-b)-(a+b)=
=3a+6b-9c-2a+4c+5c-5b-a-b=0
b)
a/4-a/2² =a/4-a/4=0
czyli mamy
=1 / (3a²m+3am)-2=2*(3a²m+3am)=6a²m+6am
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a)
3(a+2b-3c) - 2 (a-2c)+5(c-b)-(a+b)=
=3a+6b-9c-2a+4c+5c-5b-a-b=0
b)
a/4-a/2² =a/4-a/4=0
czyli mamy
=1 / (3a²m+3am)-2=2*(3a²m+3am)=6a²m+6am