Oblicz:
a) 2 log 3 + 3 log 2=
b) 3 log 4 - 4 log 2=
c) 2 log √3 + 3 log 1=
d) log log log log 10¹⁰ =
e) log₃ 6 + log₃ √0,75 =
f) log₄(3+log₃(1+log₂ 4))=
g) log₄(1+log₄(2+log₄16))=
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a)
2 log 3 + 3 log 2 = log 3^2 + log 2^3 = log 9 + log 8 = log (9*8 ) = log 72
b)
3 log 4 - 4 log 2 = log 4^3 - log2^4 = log 64 - log 16 = lig( 64/16) = log 4
c)
2 log p(3) + 3 log 1 = log ( p(3))^2 + 3*0 = log 3
d) Nie mogę odczytać wykladnika
Czy to jest 10 ?
e)
log 3 ( 6) + log 3 [ p(0,75)] = log 3 ( 3*2) + log 3 [ p(3/4)] =
= log 3 (3) + log 3(2) + log 3 [ p(3)/2 ] =
= 1 + log 3(2) + log 3 [ p(3)] - log 3 (2) =
= 1 + 1/2 = 1,5
f)
log 4 [ 3 + log 3 ( 1 + log 2(4))) =
= log 4 [ 3 + log 3 ( 1 + 2)] = log 4[3 + log 3 (3)] =
= log 4 [3 + 1] = log 4 (4) = 1
g) log4 [ 1 + log 4 ( 2 + log 4 (16))) =
= log 4 [ 1 + log 4 ( 2 + 2)) = log 4 [ 1 + log 4 (4)] =
= log 4 [ 1 + 1] = log 4 (2) = 1/2