Oblicz
2(x do kwadratu +1) - (x-5) x=
x-[1- (x+3) (x-1) ] =
2(x²+1)-(x-5)x=2x²+2-(x²-5x)=x²-5x+2
x-[1-(x+3)(x-1)]=x-[1-(x²-x+3x-3)]=x-(1-x²+x-3x+3)=x-1+x²-x+3x-3=x²+3x-4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2(x²+1)-(x-5)x=2x²+2-(x²-5x)=x²-5x+2
x-[1-(x+3)(x-1)]=x-[1-(x²-x+3x-3)]=x-(1-x²+x-3x+3)=x-1+x²-x+3x-3=x²+3x-4