Objętość pewnego graniastosłupa wynosi 270 cm³.Jego wysokość ma 6 cm.Oblicz pole podstawy tego graniastosłupa.
v= 270 cm3
H=6 cm
Pp= ?
V= Pp x H
270 = Pp x6
6Pp =270 / ;6
Pp = 45 cm 2
V=Pp*H
V=270cm³
H=6cm
270=Pp*6
270=6Pp /:6
45=Pp
Pp=45cm²
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
v= 270 cm3
H=6 cm
Pp= ?
V= Pp x H
270 = Pp x6
6Pp =270 / ;6
Pp = 45 cm 2
V=Pp*H
V=270cm³
H=6cm
270=Pp*6
270=6Pp /:6
45=Pp
Pp=45cm²