Objętość 10 moli gazu doskonałego w temperaturze 127 (stopni celcjuszy) i pod ciśnieniem 8,31 MPa wynosi ?
pV=nRT
V=nRT/p
V=10*8,31*400/(8,31*10^6)= 0,004m^3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
pV=nRT
V=nRT/p
V=10*8,31*400/(8,31*10^6)= 0,004m^3