objetosc stopu na skutek podgrzewania zwiekszyla sie p 5%. o ile procent zmiejszyla sie gestosc ( masa wlasciwa ) tego stopu? wynik podaj z dokladnoscia do 0.01%
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b = (m/((105/100)*v))*b * (105/100) = m/v = d
d - b = (105/105)*d-(100/105)*d = 1/21*d = 0.04762 = 4,76%