O liczbach a i b wiadomo, że oraz . Oblicz .
9^a = 64
( 3^2)^a = 64
( 3^a)^2 = 8^2
3^a = 8
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b = log 27 [ 1/8] = log 27 [ (1/2)^3] = 3 log 27 ( 1/2) = 3 *(1/3) log 3(1/2) = log 3(1/2)
b = log 3 [ 1/2]
================
3^( a + b) = 3^a * 3^b = 8* 3^[ log 3 (1/2) ] = 8*(1/2) = 4
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9^a = 64
( 3^2)^a = 64
( 3^a)^2 = 8^2
3^a = 8
===========
b = log 27 [ 1/8] = log 27 [ (1/2)^3] = 3 log 27 ( 1/2) = 3 *(1/3) log 3(1/2) = log 3(1/2)
b = log 3 [ 1/2]
================
3^( a + b) = 3^a * 3^b = 8* 3^[ log 3 (1/2) ] = 8*(1/2) = 4
====================================================