Question

Nomor 4 dengan caranya,kalo ga keberatan tolong sekalian no.5.

Answer 1

4. -3x + y -1 =0
Y= 3x+1
m= 3 -> -1/3(tegak lurus)

(-1,2)-> rumus: y-y1= m.(x-x1)
Y-2=-1/3(x+1)
y-2= -1/3x-1/3
___________ (x3)
3y -6 =-x - 1
Jadi: x + 3y -5


5. Rumus-> x-x1 = y-y1
---------------
x2-x1= y2-y1
(2,-3) (-4,0)
X-2 = y+3
--------------
-4-2=0+3 (Dikali silang ya)

-> 3x-6=-6y-18
Jadi, 3x+6y+12-> x+2y+4

Hello, sorry ya kalau salah ehehhee