5). 194=X bai 1/2 dikali 1,99268 kali 10 pangkat -23
X= 773,15984 kali 10 pangkat -23
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8 L
perbandingan volume =perbndgn koef
1=8L
5=40l
diket ar N=14
57,8/100×194
=112,132 jmlh ar N dlm kafein
jmlh N 112,132/14=8
Tp wkt aku cari kafein itC8H10N4O2
agak ragu sama prosentasenya
5). 194=X bai 1/2 dikali 1,99268 kali 10 pangkat -23
X= 773,15984 kali 10 pangkat -23