a.
F listrik = F Lorentz
q.E = qvb
E = vB₁
V/d = vB₁
B₁ = V/d.v
B₁ = 200/(20.10⁻³.10⁵)
B₁ = 0,1.T
b.
Melihat lokasi titik P dan muatan tepat ketika masuk medan magnet B₂ mendapat gaya Lorentz ke kanan maka muatan itu POSITIP.
c.
q.v.B₂ = mv²/R ....R = 0,5D
m/q = B₂.R/v = 0,5. 0,3/10⁵
m/q = 15.10⁻⁷ kg/C
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a.
F listrik = F Lorentz
q.E = qvb
E = vB₁
V/d = vB₁
B₁ = V/d.v
B₁ = 200/(20.10⁻³.10⁵)
B₁ = 0,1.T
b.
Melihat lokasi titik P dan muatan tepat ketika masuk medan magnet B₂ mendapat gaya Lorentz ke kanan maka muatan itu POSITIP.
c.
q.v.B₂ = mv²/R ....R = 0,5D
m/q = B₂.R/v = 0,5. 0,3/10⁵
m/q = 15.10⁻⁷ kg/C