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x⇒1 x³ - 1 x⇒1 (x - 1)(x² + x + 1)
= l i m ( 3x² +x³ + 2x + 5)
x⇒1 (x² + x + 1)
= 3 + 1 + 2 + 5
1 + 1 + 1
= 11/3