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x⇒π/4 sinx - cosx x⇒π/4 sinx - cosx
lim (cosx - sinx)(sinx - cosx)
x⇒π/4 cosx
= lim 2sinxcosx - (cos²x + sin²x)
x⇒π/4 cosx
= lim (2sinx - 1/cosx)
x⇒π/4
= 2sinπ/4 - 1/cosπ/4
= 2(1/2 √2) - 1/(1/2 √2)
= √2 - 2/√2
= √2 - √2
= 0
tidak ada jawaban yang betul