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bo masa C3H6O3 wynosi = 12u*3 + 1u*6 + 16u*3 = 90u
lub skorzystać z ogólnego wzoru na sacharydy
Cn(H2O)n = 90u
12n(2+16)n = 12n + 18n = 30n
30n = 90u
n = 3
12n(2 * 1+ 16)n = 90
12n(18)n =90
12n + 18n = 90
30n= 90 /30
n= 3
Odp: C3H6O3