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A = (2;8)
α = 60[stopni]
a = tgα = √3
więc y = √3x + b
Podstawiam wsp. pkt. A
8 = √3*2 + b
b = 8 - 2√3
Ostateczny wzór funkcji to
f(x) = √3x + 8 - 2√3.
Pozdrawiam.