andy23
A(3;4) B(5;6) wtedy rownanie prostej AB x-xA/xB-xA=y-yA/yB-yA x-3/5-3=y-4/6-4 x-3/2=y-4/2 x-3=y-4 y=x-3+4 y=x+1 poniewaz AB i CD sa rownolegle, to rownanie prostej CD y=x+n (k1=k2=1) C(3;0) x=3 y=0; podstawimy do rownania prostej CD 0=3+n n=-3 toz rownanie CD y=x-3
wtedy rownanie prostej AB
x-xA/xB-xA=y-yA/yB-yA
x-3/5-3=y-4/6-4
x-3/2=y-4/2
x-3=y-4
y=x-3+4
y=x+1
poniewaz AB i CD sa rownolegle, to rownanie prostej CD y=x+n (k1=k2=1)
C(3;0) x=3 y=0; podstawimy do rownania prostej CD
0=3+n
n=-3
toz rownanie CD y=x-3