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2 C₂H₆+7 O₂ ---> 4CO₂ + 6 H₂O
BUTAN: C₄H₁₀ +¹³/₂O₂--->4CO₂+ 5H₂O /×2
2 C₄H₁₀ + 13O₂ ---> 8CO₂+ 10H₂O
MASA CZĄSTECZKOWA ETANU: M= 2×12+6×1=30u
zawartość węgla--> 100%----30g
x%----24g
x=100%×28÷34=80%