Napisz reakcję pomiędzy kwasem mrówkowym, a : Zn (II) i Fe2 O3.
2HCOOH + Zn --> (HCOO)₂Zn + H₂
6HCOOH + Fe₂O₃ --> 2(HCOO)₃Fe + 3H₂O
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Litterarum radices amarae sunt, fructus iucundioresPozdrawiam :)
2HCOOH+Zn---->(HCOO)₂Zn+H₂
6HCOOH+Fe₂O₃--->2(HCOO)₃Fe+3H₂O
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2HCOOH + Zn --> (HCOO)₂Zn + H₂
6HCOOH + Fe₂O₃ --> 2(HCOO)₃Fe + 3H₂O
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
2HCOOH+Zn---->(HCOO)₂Zn+H₂
6HCOOH+Fe₂O₃--->2(HCOO)₃Fe+3H₂O