Napisz reakcję kwasu octowego z następującymi substancjami: Ba, Zn O, Fe (OH)3
2CH3COOH + Ba ---> (CH3COO)2Ba + H2
2CH3COOH + ZnO ---> (CH3COO)2Zn + H2O
3CH3COOH + Fe(OH)3 ---> (CH3COO)3Fe + 3H2O
2 CH₃COOH + Ba ⇒ (CH₃COO)₂Ba + H₂
2 CH₃COOH + ZnO ⇒ (CH₃COO)₂Zn + H₂O
3 CH₃COOH + Fe(OH)₃ ⇒ (CH₃COO)₃Fe + 3 H₂O
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2CH3COOH + Ba ---> (CH3COO)2Ba + H2
2CH3COOH + ZnO ---> (CH3COO)2Zn + H2O
3CH3COOH + Fe(OH)3 ---> (CH3COO)3Fe + 3H2O
2 CH₃COOH + Ba ⇒ (CH₃COO)₂Ba + H₂
2 CH₃COOH + ZnO ⇒ (CH₃COO)₂Zn + H₂O
3 CH₃COOH + Fe(OH)₃ ⇒ (CH₃COO)₃Fe + 3 H₂O