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Cr2O7(2-) + 14H(+) + 6e = 2Cr(3+) + 7H2O.
H2O2 + 2H(+) -2e = 2H2O I *3
Jeżeli do dotyczy tego samego równania reakcji redox , to:
Cr2O7(2-) + 14H(+) + 6e = 2Cr(3+) + 7H2O;
3H2O2 + 6H(+) - 6e = 6H2O.