Question

N*A*J Oblicz wartość każdego zjawiska!
DZIEKUJE

Answer 1

A)
4^-2 * 4^4 + 4^0 = 4^2 + 1 = 16 + 1 = 17
(-4)^3 : (-4)^3 - 4 = 1 - 4 = -3
(4^2)^5 : 4^7 - 4^2 = 4^10 : 4^7 - 4^2 = 4^10 : 4^7 - 4^2 = 4^3 - 4^2 = 4^2 * (4 - 1) = 48

b)
3^3 * 4^3 - 12^3 = (3 * 4)^3 - (3 * 4)^3 = 3^12 - 3^12 = 0
(-3)^-4 : (-3)^-5 + (-3)^0 = -3 + 1 = -2
(2^2)^5 : 2^8 - 2^-2 = 2^10 : 2^8 - (1/2)^2 = 2^2 - 1/4 = 4 - 1/4 = 3 i 3/4

c)
-0,5^-4 * 2^-4 - 2^-3 = -2^4 * 2^-4 - (1/2)^3 = 1 - 1/8 = 7/8
(6^-3)^-4 : 6^12 - (1/5)^-2 = 6^12 : 6^12 - 5^2 = 1 - 25 = -24
48^-3 : 24^-3 + 0,1^-3 = (48/24)^-3 + 10^3 = 2^-3 + 10^3 = (1/2)^3 + 10^3 =
= 1/8 + 1000 = 1000 i 1/8