Question

N^3-4n^2-2n+8= ?

Answer 1

N^3-4n^2-2n+8 = 3n - 8n - 2n + 8 = -7n + 8

prosze naj ;]

Answer 2

N^2(n-4)-2(n-4)=(n^2-2)(n-4)=(n-2)(n+2)(n-4) czyli n=2 lub n=-2 lub n=4

Answer 3

N^3-4n^2-2n+8 = 3n - 8n - 2n + 8 = -7n + 8