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Jeżeli z=\frac{1}{x+y} ,(x+y≠0 ,y≠0 ,z≠0 ,z-y≠0), to x wynosi :

a)\frac{zy}{y-z}

b)\frac{zy}{z-y}

c)\frac{y-z}{zy}

d)\frac{z-y}{zy}


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