Question

MTK kelas 8 ... bantu jawab ya kakak ² yg pinter

Answer 1

10.
L= Phi × r^2
L=22/7 × 7×7
L=154 cm^2

sudut POQ/360° = jring OPQ/luasLngkr
72°/360° = OPQ/ 154cm^2
1/5= OPQ× 154cm^2
OPQ=154/5
OPQ= 30.8 cm^2 (A)

11.
PGSPD
AB^2 = OP^2 - (BP+ OA)^2
=25^2 - (5 + 2)^2
=625 - 49
=576
=√576
=24 cm (B)

12.
penyelesaian,
=phi × d
= 22/7 × 140 m
=440 m = 44.000 cm

maka;
=44.000 cm/ 55 cm
=800 pohon (D)

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