Question

Mohoon bantuan nyaa!, yg serius ya

Answer 1

²log3 = a dan ³log5 = b, maka
²log3 x ³log5 = ab atau
²log5 = ab

a) ²log15 = ²log3 + ²log5 = a + ab = a(1 + b)

b) 4' log 75 = (2²)' log 75 = ² log 75^(1/2) = 1/2 ²log 75
= 1/2 (²log 15 + ²log 5) = 1/2 (a+ab+ab)
= 1/2 (a + 2ab) = 1/2 a + ab

c) 25' log 36 = (5²)' log 6² = 5' log 6 = ²log6/²log5
= (²og2 + ²log3)/(²log5) = (1 + a)/(ab)

d) ²log 5 = ab (sudah di atas)

e) 30' log 150 = ²log150/²log30
= (²log15 + ²log2 + ²log5)/(²log15 + ²log2)
= (a+ab + 1 + ab)/(a+ab+1) = (2ab + a + 1)/(a + ab + 1)

f) 100' log 50 = ²log50/²log100
= (²log2 + ²log5²)/(²log2^2 + ²log5²)
= (1 + 2 ²log5)/(2 ²log2 + 2 ²log 5)
=(1 + 2ab)/(2 + 2ab)

Answer 2

A)a^2b
b)ab+a
c)(a+1)/ab
d)ab
e)a+2ab+1/a+ab+1
f)1+2ab/2+2ab