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a' log b - b' log a
= a' log a^4 - (a^4)' log a
= 4 (a' log a) - a' log a^(1/4)
= 4(1) - 1/4 (a' log a)
= 4 - 1/4(1)
= 4 - 1/4
= 15/4
8) jika a'logb=4 dan c'logb = 4, maka a = c
dg demikian nilai dari :
[a' log (bc)^4]^(1/2
= [4 (a' log(bc) ]^(1/2)
= 4^1/2 * [a' log (bc)]^(1/2)
= 2 [a'logb + a'logc]^(1/2
= 2 [4 + a'loga]^(1/2)
= 2 [4+1]^1/2
= 2 (5^1/2)
= 2√5